x^2-40x+49=-18x-72

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Solution for x^2-40x+49=-18x-72 equation: 



x^2-40x+49=-18x-72

We move all terms to the left:

x^2-40x+49-(-18x-72)=0

We get rid of parentheses

x^2-40x+18x+72+49=0

We add all the numbers together, and all the variables

x^2-22x+121=0

a = 1; b = -22; c = +121;
Δ = b2-4ac
Δ = -222-4·1·121
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{22}{2}=11$

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